Question

16. A metal weighing 0.43 g was dissolved in 50 mL of
1 N H2SO4. The unreacted H2SO4 required 14.2 mL of
1 N NaOH for neutralisation. The equivalent weight of the
metal is
(a) 12.01 (b) 6.7 (c) 8.6 (d) 30.3​

Answer 1

Answer:

what is the volume of water to be added to 200 ml of 18 molar H2 S o4 solution to get 18 1.8 molar H2 S o4 solution?

98% by weight means 98 gm H2SO4 in 100 gm solution or 98 g H2SO4 in 2 g water.

5.5 [0.1×1000/ 18] So the required volume is 5.5 ml.

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