Question

16. A person standing at a distance of 7.5 m from 13 m high building observes a kid
slipping from the top of it. If he runs with his arms at a height 1.75 m to catch the kid.
his speed should be (g = 10 ms)
​

Answer 1

Answer:

sorry I will not giving to answer you question

Answer 2

Answer:

The correct answer will be -

The speed of the person will be 5 m/s.

Explanation:

Given in the question -

• A person is standing at a distance of 7.5 m from a 13 m high building.
• He observes a kid slipping from the top of it.
• His arms at a height of 1.75 m to catch the kid.

We have to find the speed at which he should run to catch the kid.

The kid will fall up to a distance of -

Total height of the building - the height of the arms

$13-1.75=11.25\ m$

Now we will calculate the time it will take the kid since the initial velocity is zero and a = 10 m/s²

$s = ut+\frac{1}{2}at^2\\ \\11.25 = \frac{1}{2}\times 10\times t^2 \\\\t^2 = 2.25\\\\t=1.5\ s$

So, the time taken is 1.5 s. At this time the person should reach the kid.

$s = vt\\\\7.5 = v\times 1.5\\\\v = 5\ m/s$

The speed of the person will be 5 m/s.

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