16. A person suffering from eye defect and doctor he suggested him were +1.5D power lens. Then find the
focal length of the lens and also write which type eye defect he is suffering. And also draw they
diagram showing the defect.
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Answer:
focal length=200/3 cm defect: hypermetropia
Explanation:
f=1/p p=1.5=3/2
f=2/3m
f=200/3cm
the positive power is always used for hypermetropia
the negative power is always used for myopia
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