Question

16. A person suffering from eye defect and doctor he suggested him were +1.5D power lens. Then find the
focal length of the lens and also write which type eye defect he is suffering. And also draw they
diagram showing the defect.​

Answer 1

Answer:

focal length=200/3 cm defect: hypermetropia

Explanation:

f=1/p p=1.5=3/2

f=2/3m

f=200/3cm

the positive power is always used for hypermetropia

the negative power is always used for myopia