Question

(V) A cricketer catches a 150 g ball moving at a speed of 20 ms. If he completes the
catching process in 0.1 s, the force exerted by the ball on his hands is:
(a) 30N
(b) 30 N
(c) 300 N
(d) 3000 N​

Answer 1

Answer: A cricketer catches a ball of mass 150g in 0.1s moving with speed 20m/s,then he experiences a force of Get the answers you need, now!

Explanation:

Answer 2

Given :

• Mass of the ball = 150 g = 0.15 kg
• Initial velocity (u) = 20 m/s
• Final velocity (v) = 0 m /s
• Time (t) = 0.1 s

To find :

• Force exerted by the ball

Solution :

Force is given by ,

• F = ΔP / t

we know that ,

⇒ ΔP = Pբ - Pᵢ

⇒ ΔP = mv - mu

⇒ ΔP = m(v-u)

Now let's substitute the given values in the above equation ,

⇒ ΔP = 0.15 (0-20)

⇒ ΔP = - 0.15 x 20

⇒ ΔP = - 3 kg m/s

Hence ,

⇒ F = - 3 / 0.1

⇒ F = - 30 N

The magnitude of force exerted by the ball on the hands of the cricketer is 30 N .