Math, asked by snidghabairagi, 1 month ago

16. A submarine 9 metres in height is floating on water. If į of its height is
under water, then what is the height of the submarine visible above water?

plz ans​

Answers

Answered by shreeji27
3

A submarine 39/4 m in height is floating on water is if 1/3 of its height is underwater then what is the height of the submarine visible above water

Submarine height = 39/4 m

1/3 of submarine = (1/3) * (39/4) = 13/4 m

Height visible above water = Submarine height - inside water

=> Height visible above water = 39/4 - 13/4

=> Height visible above water = 26/4

=> Height visible above water = 13/2 m = 6.5 m

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Answered by Prosnipzz
2

Answer:

ANSWER:−

9 \bold{(3)/(4) \: = 9\huge \frac{3}{4} }9(3)/(4)=9

4

3

above hight = total - under

\implies \bold{ 9 \huge \frac{3}{4} \small \: m - \huge \frac{1}{3} ( \small9 \huge\frac{3}{4}) \small m}⟹9

4

3

m−

3

1

(9

4

3

)m

\bold{ \implies9 \huge\frac{3}{4} (1 - \frac{1}{3} )m}⟹9

4

3

(1−

3

1

)m

\implies \huge \bold{ \frac{39}{4} ( \frac{3 - 1}{3})m }⟹

4

39

(

3

3−1

)m

\implies\huge \bold{ \frac{ \cancel{39} {}^{13} }{ \cancel{4} {}^{2} } \times \frac{ \cancel2}{ \cancel{3}} }⟹

4

2

39

13

×

3

2

\implies \huge \bold{\frac{13}{2} m}⟹

2

13

m

\huge \red \star \bold{ \: 6 \frac{1}{2} \: m }⋆6

2

1

m

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