Question

16) An electron moving with the velocity of 5x104 m/s enters into a uniform electric field and acquires a
uniform acceleration of 104m/s2 in the direction of its initial motion. i) Calculate the time taken in which
the electron would acquire a velocity double of its initial velocity. ii) How much distance the electron
would cover in this time​

Answer 1

Answer:

Hey!!Mate

Here is your ans:-

Explanation:

Given data:Initial velocity of the electron is,

u = 5 × 10^4 m/s

Acceleration of the electron is,

a = 10^4 m/s2

(i)

Using, v = u + at

=> 2u = u + at. [since v is double of Initial velocity (u)]

=> t = u/a = (5 × 10^4)/( 10^4) = 5 s

(ii)

Distance travelled in this time is,

S = ut + ½ at2

=> S = (5 × 10^4) × 5 + ½ × 10^4 × 5^2

=> S = 3,75,000 m

I hopes it will help you❤️❤️

Answer 2

Answer:

see the attachment given below....

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