16. An object of mass 100 kg is accelerated uniformly from a velocity
of 5 m s' to 8 m si in 6 s. Calculate the initial and final
momentum of the object. Also, find the magnitude of the force
exerted on the object.
Answers
Given :
- Mass of an object, m = 100 kg
- Initial velocity, u = 5 m/s
- Final velocity, v = 8 m/s
- Time, t = 6 seconds
To find :
- Initial momentum
- Final momentum
- Force exerted on the object
According to the question,
➞ Initial momentum = Mass × Initial velocity
➞ Initial momentum = 100 kg × 5 m/s
➞ Initial momentum = 500 kg m/s
So,the final momentum is 500 kg m/s.
➞ Final momentum = Mass × Final velocity
➞ Final momentum = 100 kg × 8 m/s
➞ Final momentum = 800 kg m/s
So,the final momentum is 800 kg m/s.
Now,
➞ v = u + at
Where,
- v = Final velocity
- u = Initial velocity
- a = Acceleration
- t = Time
➞ 8 = 5 + a × 6
➞ 8 - 5 = 6a
➞ 3 = 6a
➞ 3 ÷ 6 = a
➞ 0.5 = a
So,the acceleration is 0.5 m/s².
As we know,
➞ Force = Mass × Acceleration
Or,
➞ F = ma
➞ F = 100 × 0.5
➞ F = 50 N
So,the force exerted on the object is 50 Newton.
Answer:
Given:-
- Mass = 100 kg
- Initial velocity = 5 m/s
- Final velocity = 8 m/s
- Time = 6 sec
To Find :-
- Initial Mounmentum
- Final Mounmentum
- Force applied
Solution :-
❶ Initial Mounmentum
Initial Mounmentum = 100 × 5
Hence, Initial Mounmentum = 500 kg m/s.
❷ Final Mounmentum
Final Mounmentum = 100 × 8
Hence, Final Mounmentum = 800 kg m/s
❸ Force exerted
So, for finding force exerted we will first find Acceleration. by using newton first Equation of motion.
➵ 8 = 5 + a × 6
➵ 8 - 5 = a × 6
➵ 3 = 6a
➵ 3/6 = a
➵ a = 0.5 m/s²
Hence, Acceleration of body is 0.5 m/s².
Now,
Let's find force exerted
F = ma
➵ F = 100 × 0.5
➵ F = 50
Therefore :-
Force applied = 50 Newton