Physics, asked by gayathri034, 6 months ago

16. An object of mass 100 kg is accelerated uniformly from a velocity
of 5 m s' to 8 m si in 6 s. Calculate the initial and final
momentum of the object. Also, find the magnitude of the force
exerted on the object.​

Answers

Answered by Blossomfairy
21

Given :

  • Mass of an object, m = 100 kg

  • Initial velocity, u = 5 m/s

  • Final velocity, v = 8 m/s

  • Time, t = 6 seconds

To find :

  • Initial momentum
  • Final momentum
  • Force exerted on the object

According to the question,

Initial momentum = Mass × Initial velocity

➞ Initial momentum = 100 kg × 5 m/s

➞ Initial momentum = 500 kg m/s

So,the final momentum is 500 kg m/s.

➞ Final momentum = Mass × Final velocity

➞ Final momentum = 100 kg × 8 m/s

➞ Final momentum = 800 kg m/s

So,the final momentum is 800 kg m/s.

Now,

➞ v = u + at

Where,

  • v = Final velocity
  • u = Initial velocity
  • a = Acceleration
  • t = Time

➞ 8 = 5 + a × 6

➞ 8 - 5 = 6a

➞ 3 = 6a

➞ 3 ÷ 6 = a

➞ 0.5 = a

So,the acceleration is 0.5 m/s².

As we know,

Force = Mass × Acceleration

Or,

➞ F = ma

➞ F = 100 × 0.5

➞ F = 50 N

So,the force exerted on the object is 50 Newton.

Answered by Anonymous
4

Answer:

Given:-

  • Mass = 100 kg
  • Initial velocity = 5 m/s
  • Final velocity = 8 m/s
  • Time = 6 sec

To Find :-

  • Initial Mounmentum
  • Final Mounmentum
  • Force applied

Solution :-

Initial Mounmentum

 \sf \: initial \: mounmentum \:  = mass \times initial \: velocity

Initial Mounmentum = 100 × 5

Hence, Initial Mounmentum = 500 kg m/s.

Final Mounmentum

 \sf \: final \:mounmentum = mass \times final \: velocity

Final Mounmentum = 100 × 8

Hence, Final Mounmentum = 800 kg m/s

Force exerted

So, for finding force exerted we will first find Acceleration. by using newton first Equation of motion.

 \huge \fbox {v = u + at}

8 = 5 + a × 6

8 - 5 = a × 6

3 = 6a

3/6 = a

a = 0.5 m/s²

Hence, Acceleration of body is 0.5 m/.

Now,

Let's find force exerted

F = ma

F = 100 × 0.5

F = 50

Therefore :-

Force applied = 50 Newton

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