Question

16. At NTP, what will be the volume of molecules of 6.022 x 10 H2?
17. Calculate the number of molecules present in 0.5 moles of CO2?​

Answer 1

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Answer 2

Answer:

The volume of  6.022 x 10 molecules of hydrogen gas is equal to 6.022 x 10⁻²²L.

The number of molecules present in 0.5moles of carbon dioxide is 3.022 x 10²³.

Explanation:

• The volume of one mole any gas at NTP = 22.4 L

        The volume of 6.023 x 10²³ molecules of H₂ gas = 22.4 L

        So, volume of  6.022 x 10  molecules of H₂  $=\frac{22.4*6.023*10}{6.023*10^{23}}$

                                                                                $=6.023 *10^{23} L$

• The number of molecules in one mole of CO₂ gas = 6.023 x 10²³

      Number of molecules in 0.5 mole of CO₂ gas $=\frac{6.023*10^{23}}{2}$

                                                                                $= 3.0115*10^{23}$ molecules