Question

А
16 cm D
10. In the given figure, ABCD is a trapezium in which AD || BC,
ZABC = 90°. AD = 16 cm, AC = 41 cm and BC = 40 cm. Find the
area of the trapezium.
Hint. AB2 = (AC2-BC2).
41 cm
40 cm​

Answer 1

Answer:

Since, m∠ABC is 90°

So, AB is the height of the trapezium ABCD

Now, to find AB : By using Pythagoras theorem in ΔABC

AC² = AB² + BC²

41² = AB² + 40²

⇒ AB² = 41² - 40²

⇒ AB = 9 cm

Now, Area of the trapezium is given by the formula :

Answer 2

Answer:

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