Question

16. Find the area of triangle whose vertices are:
(1.-1): (-4.6): (-3.-5).​

Answer 1

$\huge{\bf{\underline{\underline{QuEsTion:}}}}$

Find the area of triangle whose vertices are (1,-1),(-4,6),(-3,-5)

$\huge{\bf{\underline{\underline{AnSwEr:}}}}$

$\large{\mathfrak{\underline{\pink{Formula \: of \: Area \: of \: Triangle:-}}}}$

$\large\implies\tt<u> </u> \frac{1}{2} \ [ x_1(y_2 \: - \: y_3) \: + \: x_2( y_3 \: - \: y_1) \: + \: x_3(y_1 \: - \: y_2)]$

Now;

$\large\implies\tt\frac{1}{2} \ [ 1(6 \: + \: 5) \: + \: (-4) (-5-1) \: + \: (-3)(1-6)]$

$\large\implies\tt\frac{1}{2} \ [ 1(11) \: - \: 4(-6) \: -3(-5) ]$

$\large\implies\tt\frac{1}{2} \ [ 11 \: + \: 24 \: + \: 15 ]$

$\large\implies\tt\frac{1}{2} \ [50]$

$\large\implies\tt\frac{1}{2} \times\ 50 \: = \: 25 \: sq. units$