Question

16. Find the equivalent capacitance between the points A and B of the network of capacitors shown in Fig. 2.91. ​

Answer 1

Answer:

Explanation:

The corresponding equivalent circuit is as shown in figure.  

The all capacitors on top are in series so the equivalent capacitance for top part is C  

t

​

=(1/C+1/C+1/C)  

−1

=C/3

Now this capacitance C  

t

​

 and bottom capacitance C are in parallel.

So the equivalent capacitance C  

AB

​

=C  

t

​

+C=C/3+C=4C/3