Question

16. Find the value of (cos 48° - sin 42).
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Answer 1

Answer:

0

Step-by-step explanation

Cos 48°- cos(90-48°)

Cos 48°-cos 48°

0

Answer 2

AnswEr:

$\bf\ :$$\normalsize\implies\sf\ (cos48^{\circ} - sin42^{\circ} ) \: = \: 0$

$\underline{\bigstar\:\textsf{According \: to \: the \: question:-}}$

$\scriptsize\sf{\: \: \: \: \: \:[\therefore\ \: \pink{ cos\theta = sin(90^{\circ} - \theta)}] }$

$\normalsize\ : \implies\sf\ (cos48^{\circ} - sin42^{\circ})$

$\normalsize\ : \implies\sf\ [cos48^{\circ} - sin(90^{\circ} - 48^{\circ})]$

$\normalsize\ : \implies\sf\ (cos48^{\circ} - cos48^{\circ})\: = \: 0$

$\ : \implies{\boxed{\sf{(cos48^{\circ} - sin42^{\circ} = 0}}}$