Question

16. If -2 and 3 are the zeros of the quadratic polynomial x? + (a +1)x+ b
then​

Answer 1

Answer:

a = -14, b=-26

Step-by-step explanation:

I think you asked the values of a and b

-2 and 3 are the zeroes of the polynomial x²+(a+1)x+b

Let p(x) = x²+(a+1)x+b

p(-2)=0

4-2a-2+b=0

2-2a+b=0

2a-b=2..........(1)

p(3)=0

9+3a+3+b=0

12+3a+b=0

3a+b=-12...........(2)

(1)-(2)

-a=14

a = -14

Substitute a=-14 in (1)

2(-14)-b = 2

-28-b = 2

-b=26

b = -26

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