Question

16. If 3 is a zero of x2+2x-k. find k. .​

Answer 1

Answer:

$k = 15$

Step-by-step explanation:

${x}^{2} + 2x + k$

If 3 is a zero of the given equation then ,

$({3})^{2} + 2(3) - k = 0 \\ = > 9 + 6 - k = 0 \\ = > 15 - k = 0 \\ = > 15 = k \\ = > k = 15$

Answer 2

Answer:

Here is the answer!!

If 3 is one of zeroes of the polynomial x^2+2x+k which means x=3 will satisfy it.

Then,

x^2+2x-k=0

(3)^2+2(3)-k=0

9+6-k=0

k=15

Hence, k=15

Hope it helps you dear!!!!