Question

16. If tan tetha + cot tetha = 5, then the value of tan²tetha + cot² tetha is
(A) 23
(B) 25
(C) 27
D)15
​

Answer 1

Step-by-step explanation:

tan∅+cot∅= 5

on squareing both side

(tan∅+cot∅)²=5²

tan²∅+cot²∅+2tan∅×cot∅= 25

tan²∅+cot²∅+2tan∅×1/tan∅= 25

tan²∅+cot²∅+2=25

tan²∅+cot²∅=23

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