16. In AABC, AB = AC and AP = AQ. Prove that
CP = BQ.
А
B
P
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Step-by-step explanation:
In the adjoining figure P and Q are two points on equal sides AB and AC of an isosceles triangle ABC such that AP = AQ , prove that BQ = CP
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ANSWER
REF. Image.
Given AB=AC
and AP=AQ
Thus
AB-AP=AC-AQ
[BP=CA ] [from figure ]
now InΔBCP & ΔBCQ
BP = CQ
∠c=∠c [common]
and BC=BC [common]
∴ΔBCP≃ΔBCQ [SAS congruency]
now
[BQ=CP] [corresponding parts of congruent triangles]
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