Math, asked by sanskar4038, 1 year ago

16. In the given figure, ABCD is a parallelogram.
X and Y are respectively the mid-points of the
sides AB and CD of the parallelogram ABCD.
AY and DX are joined intersecting each other
at P. CX and BY are joined intersecting each
other at Q. Prove that PXQY is a
parallelogram.​

Answers

Answered by ankursinghtomar2606
9

Hope this Would be helpful to you :)

Attachments:
Answered by aliasgar47
7

BX = 1/2AB

DY = 1/2CD

AB= CD OPP SIDE OF ||GM

1/2AB = 1/2 CD

BX = DY

ALSO BX || DY

SO DXBY ||GM

SIMILARLY AXCY ||GM

AY || CY

PY || QX. 1

DX || BY

PX|| QY 2

FROM 1 & 2

PXQY ||GM

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