Question

16. In the given figure, ABCD is a rhombus. Diagonals
AC and BD intersect each other at E. If Z1 = 50°
then ZBCD =​

Answer 1

Answer:

80°

Step-by-step explanation:

ABCD is a rhombus .Diagnoals AC and BD intersect each other at E .

Given ,1 = 50 °

BD bisects ABC ( by property of rhombus )

so ABC = 2× 50° = 100°

ABC + BCD = 180 ° ....( interior angles on the same side of transversal )

(BCD = 180 ° - ABC = 100 ° ) = 180° - 100° = 80 °