Question

16. in the given figure (not drawn to scale). ABCD is a
square. Find the value of x.

answer quickly ​

Answer 1

Answer:

x= 120°

Explanation:

in ∆ XOB

<XOB= 75° ( VERTICALLY OPP. ANGLES)

<OBX = 45° ( ALT. INT. ANGLES , diagonal of square bisects the angle)

therefore,

<OXA=75+45= 120° ( EXTERIOR ANGLE OF A TRIANGLE )

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