Math, asked by kaurpragan18, 9 months ago

16. la the alongside diagram, the bisectors of
interior angles of the parallelogram PQRS
enclose a quadrilateral ABCD.
S
R
ཆུa,ནa
B
C
180
14
6
R
Show that
(i) ZPSB + ZSPB = 90° (ii) ZPBS = 900
(iii) ZABC = 90°
(iv) ZADC = 90°
ZA = 90° (6) ABCD is a rectangle
Thus, the bisectors of the angles of a
parallelogram enclose á rectangle.​

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Answered by mystery266
0

Answer:

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Answered by sumathinathella
0
I can’t understand your question
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