Question

16) Length of one of the diagonals of a
rectangle whose sides are 10 cm and 24
cm is ...​

Answer 1

Answer:

26cm

Step-by-step explanation:

Let the rectangle be ABCD

Length =24cm=AB=CD

Breadth = 10cm=BC=DA

Diagonal =?

If we look it becomes a triangle ADC right angled at D .

So by Pythagoras theorem

AD^2+DC^2=AC^2

10^2+24^2=AC^2

100+576=AC^2

676=AC^2

Thus AC= 26cm.

Therefore length of diagonal is 26cm

Hope it is correct.

Answer 2

Answer:

Let's draw the figure.

Here, the length of ABCD = BC = 24 cm.

Breadth of ABCD = CD = 10 cm.

Here, you can see that ΔBCD is a right-angled triangle. We can easily use Pythagoras theorem:

BD²=CD²+BC²

BD²=10²+24²

BD²=100+576

BD=√676

BD=26 cm.

${\large{\mathfrak{\underbrace{\blue{LENGHT \:\: OF \:\: DIAGONAL = 26 cm. }}}$

$HOPE \:\: THIS \:\: HELPS \:\: :D$