Math, asked by prathmesh3362, 1 year ago

16 persons can reap 1\5 field in 6 days. how many persons with same efficiency are required to reap the rest of the field

Answers

Answered by RvChaudharY50
0

Solution :-

given that,

→ M1 = 16 persons

→ M2 = Let x persons

→ D1 = 6 days

→ D2 = 8 days

→ W1 = (1/5) th field

→ W2 = (4/5) th field { Rest }

since efficiency is same ,

→ (M1 * D1)/W1 = (M2 * D2)/W2

→ 16 * 6 * (4/5) = x * 8 * (1/5)

→ 96 * 4 = 8x

→ x = 48 persons (Ans.)

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