16 persons can reap 1\5 field in 6 days. how many persons with same efficiency are required to reap the rest of the field
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Solution :-
given that,
→ M1 = 16 persons
→ M2 = Let x persons
→ D1 = 6 days
→ D2 = 8 days
→ W1 = (1/5) th field
→ W2 = (4/5) th field { Rest }
since efficiency is same ,
→ (M1 * D1)/W1 = (M2 * D2)/W2
→ 16 * 6 * (4/5) = x * 8 * (1/5)
→ 96 * 4 = 8x
→ x = 48 persons (Ans.)
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