Question

16) Solve for x : x^2 – (2b – 1)x+(b^2 – b – 20) = 0​

Answer 1

Step-by-step explanation:

x

2

−(2b−1)x+b

2

−b−20=0

The roots are:

x=

2

(2b−1)±

(2b−1)

2

−4×(b

2

−b−20)

=

2

(2b−1)±

4b

2

+1−4b−4b

2

+4b+80

=

2

(2b−1)±

81

=

2

(2b−1)±9

∴x=

2

2b−1+9

=b+4