Question

16. The angles of elevation of the top of a tower from two points at a distance of 4 m an
Om from the base of the tower and in the same straight line with it are complementar
Prove that the height of the tower is 6 m.​

Answer 1

Answer:

Given that AB is the tower

P,Q are the point at distance 4m and 9m resp.

Also, PB=4m QB =9m

& ngle of elevation from P is A

Angle of elevation from Q is B.

Given a and B are supplemantry.

a +B = 90°

we need to prove AB = 6m