Question

16. The base and height of a triangle are in the ratio 4:3. If the base is increased by 4 cm and the height is decreased by 2 cm, the area of the triangle remains the same. Find the base and the height​

Answer 1

Answer:

Let the b and h be 4x and 3x.

Area=1/2×4x×3x=6x

If b is increased

b=4x+4

If h is decreased

h=3x-2

A.T.Q

1/2×{(4x+4)×(3x-2)}=6x

1/2×(36x-8)=6x

18x-4=6x

12x=4

x=1/3

b=4x=4/3cm

h=3x=1cm

Step-by-step explanation:

Please mark as brainliest.

Answer 2

QUESTION:

The base and height of a triangle are in the ratio 4:3. If the base is increased by 4 cm and the height is decreased by 2 cm, the area of the triangle remains the same. Find the base and the height

ANSWER:

LET BASE BE 4k

HEIGHT IS 3K

$\\ \\ \\ \\ Area= \frac{1}{2} \times base \times height \\ \\ \\ \\ 216 = \frac{1}{2} \times 4k \times 3k \\ \\ \\ \\ 6 {k}^{2} = 216 \\ \\ \\ \\ {k}^{2} = 36 \\ \\ \\ \\k = \sqrt{36} \\ \\ \\ \\ k = 6cm \\ \\ \\ \\ height = 3k = 3(6) = 18cm \\ \\ \\ \\ base = 4k = 4(6) = 24cm \\ \\ \\ \\ so \: \: height \: \: = \: \: 18cm \\ \: \: and \\ \: \: base \: \: = \: \: 24cm$