Math, asked by Haggupav, 6 hours ago

1/√5+2√3-√7=x find value of x​

Answers

Answered by baby154190
0

Answer:

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Answered by Shreyanshijaiswal81
1

\frac{ 1  }{  \sqrt{ 5  }    }  + \frac{ 2  }{  \sqrt{ 3  }    }  - \sqrt{ 7  }  =x

\frac{\sqrt{5}}{\left(\sqrt{5}\right)^{2}}+\frac{2}{\sqrt{3}}-\sqrt{7}=x

\frac{\sqrt{5}}{5}+\frac{2}{\sqrt{3}}-\sqrt{7}=x

\frac{\sqrt{5}}{5}+\frac{2\sqrt{3}}{\left(\sqrt{3}\right)^{2}}-\sqrt{7}=x

\frac{\sqrt{5}}{5}+\frac{2\sqrt{3}}{3}-\sqrt{7}=x

\frac{3\sqrt{5}}{15}+\frac{5\times 2\sqrt{3}}{15}-\sqrt{7}=x

\frac{3\sqrt{5}+5\times 2\sqrt{3}}{15}-\sqrt{7}=x

\frac{3\sqrt{5}+10\sqrt{3}}{15}-\sqrt{7}=x

\frac{1}{5}\sqrt{5}+\frac{2}{3}\sqrt{3}-\sqrt{7}=x

x=\frac{1}{5}\sqrt{5}+\frac{2}{3}\sqrt{3}-\sqrt{7}  \:  \: Answer

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