Question

16. The faces of a die bear numbers 0,1,2,3,4,5. If the die is rolled twice, then find
the probability that the product of digits on the upper face is zero.
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Answer 1

Step-by-step explanation:

Sample space, S = {(0, 0), (0,1), (0,2), (1,0), (1,1), (1,2), (2,0), (2,1), (2,2), (3.0), (3,1), (3,2), (4.0), (4,1), (4,2), (5.0), (5,1), (5,2) } ∴ n(S) = 36 Let A be the event that the product of digits on the upper face is zero. ∴ A = {(0, 0), (0, 1), (0, 2), (0, 3), (0, 4), (0, 5), (1,0), (2, 0), (3,0), (4, 0), (5,0)} ∴ n(A) = 11 ∴ P(A) = n(A)n(S)n(A)n(S) ∴ P(A) = 11/36 ∴ The probability that the product of the digits on the upper face is zero is 11/36.Read more on Sarthaks.com - https://www.sarthaks.com/847643/the-faces-die-bear-numbers-the-die-rolled-twice-then-find-the-probability-that-the-product