Question

the distance between point P (2, 2) and Q(5, x) is the 5cm then the value of x=?​

Answer 1

Answer:

We have,

P=(2,2),Q=(5,x) and PQ=5

We know that

d2=(x2−x1)2+(y2−y1)2

Therefore,

PQ2=(5−2)2+(x−2)2

52=(3)2+(x−2)2

25=9+(x−2)2

(x−2)2=16

x−2=±4

x=6 or x=−2

Hence, this is the answer.

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Answer 2

Answer:

-2

Step-by-step explanation:

GIVEN that,

If the distance between point P (2,2) and Q(5,X) is 5.

To find : The value of x.

The distance is d=5.

Therefore, the value of X are 6,-2.

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