16. The number of oxalic acid molecules in 100 mL of 0.02 N oxalic acid is
A)12.05 x 1023
B) 12.05 x 1020
C) 12.05 x 1021
D) 6.023 x 1020
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1
Answer:
Molarity= Valency factor
Normality
= 2/0.02
=0.01 M
No. of molecules in one molar solution =6.02×10
23
No. of molecules in 100 mL of 0.01 M oxalic acid solution
=0.01×6.02×10^23×100/1000
=6.02×10^20
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