16. The product of 7 consecutive natural numbers is
always divisible by
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SOLUTION:
We know that a number is divisible by 6, if the number is divisible by both 2 and 3
example 1: let the three consecutive numbers be 7,8 and 9.
product of numbers
7\times8\times9=5047×8×9=504
units digit of the number = 4, so it is divisible by 2.
now sum of the digit = 5+0+4=9 which is a multiple of 3.
so, 504 is divisible by both 2 and 3 so 504 is divisible by 6.
hence verified.
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