Question

16.The value of sin²90° + sin0°- sin245º. cos²45° is​

Answer 1

Answer:

Step-by-step explanation:

Given,

sin^2 90° + sin 0° - sin^2 45° × cos^2 45°

= ( 1 )^2 + ( 1 ) - ( 1 / √2 )^2 × (1 / √2 )^2

= 1 + 1 - [ ( 1 )^2 / ( √2 )^2 ) ] × [ ( 1 )^2 / ( √2 )^2 ]

= 2 - ( 1 / 2 ) × ( 1 / 2 )

= 2 - ( 1 / 4 )

= 8 - 1 / 4

= 7 / 4 is the answer.