Question

16. The width of a rectangle is two-thirds its length. If the perimeter is 180 metres, find the
dimensions of the rectangle.
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Answer 1

Solution:

It is given that width of a rectangle is two - thirds its length.

Let -

→ Length = x m.

→ Width = 2/3x

Also, it is given that perimeter of rectangle is 180 m.

→ 2(B + L) = 180

→ 2(2/3x + x) = 180

→ 2/3x + x = 180/2

→ 2/3x + x = 90

→ (2x + 3x)/3 = 90

→ 5x = 90 × 3

→ 5x = 270

→ x = 270/5

→ x = 54 m

Hence, length of rectangle is 54 m.

Now,

→ Width = 2/3x

→ Width = 2/3 × 54

→ Width = 36 m

Hence, width of rectangle is 36 m.

______________________

Answer:

• Length = 54 m
• Width = 36 m

Answer 2

Answer: Length = 54 m, width = 36 m.

Step-by-step explanation:

Given:

Width of rectangle = ⅔ of its length.

Perimeter = 180 metres.

To find: Dimensions of rectangle. (length and width)

Solution:

Let the length of rectangle be 'x' metres.

Thus, its width = ⅔ x

Perimeter of rectangle = 2 [ length + width ]

180 = 2 [ x + ⅔ x ]

180 = 2 [ (3 + 2 / 3)x ]

180 = 2 [ ( 5 / 3 )x ]

180 = 10/3x

540 / 10 = x

x = 54 metres.

Thus, the length of rectangle is 54 metres.

Width = 2/3 × 54

= 36 metres.

Thus, the dimensions (length and width) are 54 m and 36 m respectively.