16. Which of the following has the maximum number
of moles?
(1) 112 g of Na
(2) 50 g of Ne
(3) 40 g of He
(4) 60 g of C
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Answer:
1) no. of moles of Na = 112÷ 23 = 4.8
2) no. of moles of Ne = 50 ÷ 20 = 2.5
3) no. of moles of He = 40÷ 4 =10
4) no. of moles of C = 60÷14 =4.2
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