Question

16200 मी क्षेत्रफल वाले वर्ग का विकर्ण ज्ञात कीजिए।​

Answer 1

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Given :-

$\sf{Area \: of \: square = 16,200 \: m^{2}}$

To Find :-

$\sf{Diagonal \: of \: square = ? \: }$

Using Formula :-

$\sf{Area \: of \: square = (side)^{2}}$

$\sf{Diagonal \: of \: square =\sqrt{2}a}$

Solution :-

$\sf{Area \: of \: square = 16,200 \: m^{2}}$

$\sf{a^{2} = 16,200}$

$\sf{a =\sqrt{16,200}}$

$\sf{a =\sqrt{(162\times 100)}}$

$\sf{a =\sqrt{(2\times 81\times 100)}}$

$\sf{a =\sqrt{(2\times 9^{2}\times 10^{2})}}$

$\sf{a =\sqrt{2\times (9\times 10)^{2}}}$

$\sf{a =\sqrt{2\times (90)^{2}}}$

$\sf{a =90\sqrt{2} \: m}$

Diagonal of square -

$\sf{\sqrt{2}a}$

$\sf{\sqrt{2}\times 90\sqrt{2}}$

$\sf{90\times 2}$

$\sf{180 \: metre}$

Answer 2

Answer

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