168 cones each of diameter 7 cm and height 6 cm are melted to form a metallic hemisphere. Find the radius of hemisphere and the total surface area.
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Total volume of cones = 168 × 1/3 × π r²h = 4116 π cm³ = Volume of hemisphere
So 2/3 π R³ = 4116 π
or R = (6174)^(1/3)
Total surface area = 3πR²
So 2/3 π R³ = 4116 π
or R = (6174)^(1/3)
Total surface area = 3πR²
Answered by
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radius of hemisphere is 7/2 or 3.5
the total surface area of the solid = CSA of hemisphere + CSA of cone
= 2 pie r^2 + pie r l
slant hight = root 45.75
=2× 22/7×7/2×7/2 +22/7×7/2 × root 45.75
= 11×7+11× root 45.75
= 77 + 11 root 45.75 is the TSA of the solid
the total surface area of the solid = CSA of hemisphere + CSA of cone
= 2 pie r^2 + pie r l
slant hight = root 45.75
=2× 22/7×7/2×7/2 +22/7×7/2 × root 45.75
= 11×7+11× root 45.75
= 77 + 11 root 45.75 is the TSA of the solid
Khushiakherajot:
oh sorry for that answer
actually my maths is very poor
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