Question

(16a^4-8a^2+1)÷4a^2 +(4a^2-1)÷a​

Answer 1

Answer:

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Answer 2

Answer:(16a^4+16a^3-8a^2-4a+1)/4a^2

Step-by-step explanation:

Given- (16a^4-8a^2+1)÷4a^2+(4a^2-1)÷a

To Find- short answer

Solution- LCM of 4a^2 and a is 4a^2

Now, adding both term

(16a^4-8a^2+1)+4a(4a^2-1)/4a^2

Or( 16a^4-8a^2+1+16a^3-4a)/4a^2

Or (16a^4+16a^3-8a^2-4a+1)/4a^2