Question

16a²+40ab+25b², Factorize the given equation.

Answer 1

Hey!!!!

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We have

16a² + 40ab + 25b² = 0

Here a x c = 16 x 25

=> a x c = 400

Thus

=> 16a² + 20ab + 20ab + 25b² = 0 (20ab x 20ab = 400a²b²)

=> 4a(4a + 5b) + 5b(4a + 5b) = 0

=> (4a + 5b)² = 0

Thus the zeros are - 5b/4a and -5b/4a

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Hope this helps ✌️

Answer 2

Answer:

( 4a + 5 )( 4a + 5 )

Step-by-step explanation:

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We know the algebraic identity:

x² + 2xy + y² = ( x + y )²

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16a² + 40ab + 25b²

= ( 4a )² + 2×4a×5b + ( 5b )²

= ( 4a + 5b )²

= ( 4a + 5b )( 4a + 5b )

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