Math, asked by sbk39, 7 months ago

16a2bc - 64 b3c
Factorise

Answers

Answered by prafulpandey

0

Answer:

16bc(a2 - b2)

16bc(a+b)(a-b)

Answered by Anonymous

0

16a²bc - 64b³c

= 16bc(a²-4b²)

= 16bc{(a)²-(2b)²}

= 16bc(a+2b)(a-2b)

Hope, it helps you

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