Question

16x^4-(z-x)^4 how to factoise it

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Answer 1

Answer:

$16x {}^{4} - (z - x) {}^{4} \\ (4x {}^{2} ) {}^{2} -{(z - x) }^{2} {}^{2} \\ (4x^{2} - (z - x) {}^{2} )(4x {}^{2} + (z - x)^{2} ) \\ 4x {}^{2} = (z - x) ^{2} \\either \: 2x = z -x \\ 3x = z \\ or \: 4x {}^{2} = - (z - x)$