(16x⁴-81y⁴) by (2x-3y) divide the above question
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Answered by
2
(4x^2+9y^2)(2x+3y) will be the answer. Expand it.
Answered by
3
Hi ,
( 16x⁴ - 81y⁴ )
= ( 4x² )² - ( 9y² )²
= ( 4x² + 9y² ) ( 4x² - 9y² )
= ( 4x² + 9y² ) [ ( 2x )² - ( 3y )² ]
= ( 4x² + 9y² )( 2x + 3y ) ( 2x - 3y )---( 1 )
Now ,
(16x⁴ - 81y⁴ )/( 2x-3y ) = ( 1 ) / ( 2x- 3y )
= (4x² + 9y²)(2x + 3y)(2x - 3y)/(2x-3y )
= ( 4x² + 9y² ) ( 2x + 3y )
I hope this helps you.
:)
( 16x⁴ - 81y⁴ )
= ( 4x² )² - ( 9y² )²
= ( 4x² + 9y² ) ( 4x² - 9y² )
= ( 4x² + 9y² ) [ ( 2x )² - ( 3y )² ]
= ( 4x² + 9y² )( 2x + 3y ) ( 2x - 3y )---( 1 )
Now ,
(16x⁴ - 81y⁴ )/( 2x-3y ) = ( 1 ) / ( 2x- 3y )
= (4x² + 9y²)(2x + 3y)(2x - 3y)/(2x-3y )
= ( 4x² + 9y² ) ( 2x + 3y )
I hope this helps you.
:)
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