16x⁴-81y⁴, Factorize the given equation.
Answers
Answered by
17
hello mate!.....
▪ given......
16x^4-81y^4
(2x)^4 - (3y)^4
we know.....
(x+y) (x-y) = (x^2 -y^2)
[ (2x)^2+(3y)^2 ] [(2x)^2 -(3y)^2 ]
(4x^2+9y^2) (2x+3y) (2x-3y)
hope it helps u dear....
▪ given......
16x^4-81y^4
(2x)^4 - (3y)^4
we know.....
(x+y) (x-y) = (x^2 -y^2)
[ (2x)^2+(3y)^2 ] [(2x)^2 -(3y)^2 ]
(4x^2+9y^2) (2x+3y) (2x-3y)
hope it helps u dear....
Answered by
11
Answer:
(4x²+9y²)(2x+3y)(2x-3y)
Step-by-step explanation:
*********************************
We know the algebraic identity:
a² - b² = ( a + b )( a - b )
********************************
16x⁴ - 81y⁴
= ( 4x² )² - ( 9y² )²
= ( 4x² + 9y² )( 4x² - 9y² )
= (4x² + 9y²)[ (2x)² - (3y)² ]
= (4x²+9y²)(2x+3y)(2x-3y)
••••••
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