16xsquare+24xy+9ysquare
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Answer:
16x^2 + 24xy + 9y^2
= (4x)^2 + 2 × 4x × 3y + (3y)^2
= (4x + 3y)^2
= (4x + 3y) (4x + 3y)
Answered by
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Answer:
We know 16x² +24xy+9y² = (4x)² + 2(4x)(3y)+(3y)²
We know appropriate identities is x² + 2xy + y² =(x+y)²
Here x = 4x and y = 3y
Thus (4x)² + 2(4x)(3y) + (3y)² =(4x+3y)²
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