Question

17(2-x)/1-7x+5(x+12)/7x-1=

Answer 1

Answer:33+108+5x^2/7

Step-by-step explanation:

Any expression divided by 1 remains the same

17(2-x)-7x+5*x+12/7*x-1

Calculate the product

5*x+12*x=

5x*(x+12)/7

Distribute 17 through the parenthesis

17(2-x)=

34-17x

Distribute 5x through the parenthesis 5x*(x+12)= 5x^2 + 60x

Subtract the numbers 34 and -1= 33

then do -17x-7x=-24x

Right u should be having this:

33-24x + 5x^2+60x/7

If you have this then write all numerators above the common denominator

-168x+5x^2+60x/7

Solve the like terms

-168x+60x=-108x

Ur answer will be 33+ -108+5x^2/7

Answer 2

Answer:

$=\dfrac{-2(13 + 11x)}{1-7x}$

Step-by-step explanation:

$\dfrac{17(2 - x)}{1-7x} + \dfrac{5(x + 12)}{7x -1 }$

$=\dfrac{17(2 - x)}{1-7x} - \dfrac{5(x + 12)}{1 - 7x}$

$=\dfrac{17(2 - x) - 5(x + 12)}{1-7x}$

$=\dfrac{34 - 17x - 5x - 60}{1-7x}$

$=\dfrac{-26 - 22x}{1-7x}$

$=\dfrac{-2(13 + 11x)}{1-7x}$