17. 2x2 + ax-a² = 0
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Answer:
Step-by-step explanation:
2x²+ax-a²=0
/* Splitting the middle term, we get
=> 2x²-ax+2ax-a² =0
=> x(2x-a)+a(2x-a) = 0
=> (2x-a)(x+a)=0
=> 2x-a = 0 Or x+a=0
Therefore,
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