Question

17. 2x² + ax - a² = 0​

Answer 1

Step-by-step explanation:

2x²+ax-a²=0,

x²+ax+x²-a²=0,

x(x+a)+(x+a)(x-a)=0,

(x+a) [x+(x-a)]=0,

(x+a)(2x-a)=0,

if

x+a=0,

then

x=-a,

and if

2x-a=0,

then

x=a/2