Question

17. | A 0.24g sample of a compound of oxygen and boron was found by analysis to
contain 0.096g of boron and 0.144g of oxygen. Calculate the percentage
composition of the compound by weight.
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Answer 1

Answer:

Total mass of compound = 0.24 g

Mass of boron in it = 0.096 g

Therefore % composition by weight of boron = (Mass of boron/ Total mass of compound)*100

= (0.096/0.24)*100

= 40 %

Mass of oxygen in the compound = 0.144 g

Therefore % composition by weight of oxygen = (Mass of oxygen/ Total mass of compound)*100

= (0.144/0.24)*100

= 60 %.

The compound is made up of only boron and oxygen, therefore the % composition of the componenets sum to 100% (60% + 40%)

Answer 2

Answer:

Thus, if P(x, y) is any point on AB, then x = a. Hence, the equation of a straight line parallel to y-axis at a distance a from it is x = a. The equation of y-axis is x = 0, since, y-axis is a parallel to itself at a distance 0 from it.

Explanation:

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