Question

At a dinner party, every two guests used a bowl of soup between them, every three guests used a bowl of rice between them and every four used a bowl of salad between them. If there were 78 dishes altogether, then the number of guests present at the party is

Answer 1

Answer:

72

Step-by-step explanation:

First let's find the LCM of 2, 3 and 4

LCM is 12

The solution that we are seeking is the value of n that satisfies the following equation

$n( \frac{12}{2} + \frac{12}{3} + \frac{12}{4} ) = 78$

$n \times (13) = 78$

$n = 6$

Therefore the no of guests is

$n \times lcm = 6\times 12 = 72$