Question

17. A bag contains 8 red, 6 black and 4 white balls. A ball is drawn at random from the bag, find the probability the ball drawn is (i) White (ii) Black (iii) Red (IV) neither red nor black

Answer 1

Answer:

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Step-by-step explanation:

Total no. of balls in the bag is 18 (8 red, 4 black and 6 white)

Solution(i):

No. of red or white balls in bag is 14 (8 red and 6 white)

Therefore, 14C1( Selecting 1 out of 14 items) times out of 18C1( Selecting 1 out of 18 items) a red or white ball is picked.

Let E be the event of drawing a red or white ball from bag

We know that, Probability P(E) =(Total no.of possible outcomes)(No.of favorable outcomes)=18C114C1=1814=97

Solution(ii):

No. of non-black balls in bag is 14 (8 red and 6 white)

Therefore, 14C1( Selecting 1 out of 14 items) times out of 18C1( Selecting 1 out of 18 items) a non-black ball is picked.

Let E be the event of drawing a non-black ball from bag

We know that, Probability P(E) =(Total no.of possible outcomes)(No.of favorable outcomes)=18C114C1

Answer 2

Answer:

i) 2/9

ii) 1/3

iii) 4/9

iv) 2/9

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Step-by-step explanation: