Math, asked by sanjoysenchowdhury, 19 days ago

17) A closed box is varnished on the outside at the rate of 5 p per cm. What is the total cost of varnishing a box of length 50 cm, breadth 40 cm and height 30 cm?​

Answers

Answered by VaibhaSingh
0

Answer:

TSA= 2(lb+bh+hl)

TSA= 2(50x40+40x30+30x50)

TSA= 2(2000+1200+1500)

TSA= 2(4700)

TSA= 9800m2

Cost of 1cm2 = Rs. 5

Therefore cost of 9800 cm2 = 9800x5

= Rs. 49,000

Answered by LibaShahed
1

Answer:

In this question we will use Total Surface Area which is 2(lh+bh+lb)

length = 50 cm

breadth= 40 cm

height= 30 cm

so total surface area= 2( 50*30+40*30+50*40)

total surface area= 9400cm sq

Cost per sq cm= 5 Rs

Therefore, for 9400 cm sq= 9400*5= 47000 Rs

Answer:- ₹47000

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