Question

17. A hydrogen atom is in its third excited state. (a) How many spectral lines can be emitted by it before coming to the ground
state ? Show these transitions in the energy level diagram. (b) In which of the above transitions will the spectral line of shortest
wavelength be cmitted ?
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Answer 1

Answer:

(a) Here n2 = 3 n1 = 1 Now, (n2−n1)×(n2−n1+1)2(n2−n1)×(n2−n1+1)2 = (3−1)×(3−1+1)2(3−1)×(3−1+1)2 = (2×3)2(2×3)2 = 3

(b) And since n = 3 to n =1 has a higher energy emitted than from n =2 to n=1, the one with the higher energy emitted would have the shorter wavelength as Wavelength and Energy are inversely related.

Explanation:

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